Linear Programming Model (Maximization)
Carrefour Company is involved in the production of two items namely dining tables and dining chairs. The resources needed to produce these two items are twofold, namely machine time for automatic processing and craftsman time for hand completion. The table below gives the amount of time in minutes for each item: (Let X represents Chairs and Y represents Tables)Machine time | Craftsman time | |
X | 13 | 20 |
Y | 19 | 29 |
Carrefour Company has 40 hours of machine time and 35 hours of crafts time in the next working week. The cost of machine time is AED 10 per hour worked and craftsman time costs AED 2 per hour worked. The machine and craftsman not working times will incur no costs. The revenue received for each item produced with the assumption that all production is sold is AED 20 for chairs and AED 30 for tables.
The company has won a contract to produce 10 chairs per week for a particular customer.
Formulate the problem of deciding how much to produce per week as a linear program.
Solve this linear program graphically.
The company has a specific contract to produce 10 items of X per week for a particular customer.
Solution
Let:
- x be the number of items of Chairs
- y be the number of items of Tables
Then the Linear Programming model is:
Maximize
20x + 30y - 10(machine time worked) - 2(craftsman time worked)
Subject to:
13x + 19y <= 40(60) machine time
20x + 29y <= 35(60) craftsman time
x >= 10 contract
x, y >= 0
So that the objective function will become:
Maximize
20x + 30y - 10(13x + 19y)/60 - 2(20x + 29y)/60
That is, maximize
17.1667x + 25.8667y
Subject to:
13x + 19y <= 2400
20x + 29y <= 2100
x >= 10
x, y >= 0
Solving simultaneously, we have that x=10 and y=65.52 with the value of the objective function being AED1866.5
So we can say production of 10 chairs and 66 tables will bring a maximum profit of AED 1866.5
Solving it graphically, it is clear from the diagram above that the maximum occurs at the intersection of x=10 and 20x + 29y <= 2100.
Transportation Model
Carrefour would assign the most efficient transportation company, for 4 different towns in the country, 4 transportation companies are chosen. The assignment model below will determine which company transport to which town.
The first step is to find the biggest number.
Stage | A | B | C | D |
1 | 39 | 27 | 30 | 37 |
2 | 46 | 40 | 43 | 27 |
3 | 37 | 34 | 35 | 27 |
4 | 30 | 27 | 29 | 42 |
Subtract it from each and every cell
Stage | A | B | C | D |
1 | 7 | 19 | 16 | 9 |
2 | 0 | 6 | 3 | 19 |
3 | 9 | 12 | 11 | 19 |
4 | 16 | 19 | 17 | 4 |
Subtracting the smallest number of each row with the whole row
Stage | A | B | C | D |
1 | 0 | 12 | 9 | 2 |
2 | 0 | 6 | 3 | 19 |
3 | 0 | 3 | 2 | 10 |
4 | 12 | 15 | 13 | 0 |
The next step is column deduction; cover all zeros with less than 4 lines?
Stage | A | B | C | D |
1 | 40640-5080000 | 12 | 9 | 29210-508002 |
2 | 0 | 6 | 3 | 19 |
3 | 0 | 3 | 2* | 10 |
4 | 12 | 15 | 13 | 0 |
The smallest number is subtracted from all the cells
Stage | A | B | C | D |
1 | 501652032000 | 10 | 361952032007 | 482602032002 |
2 | 0 | 4 | 1 | 19 |
3 | 0 | 1* | 0 | 10 |
4 | 12 | 13 | 11 | 0 |
The smallest number is subtracted from all the cells
Stage | A | B | C | D |
1 | 501652159000 | 9 | 7 | 482602159002 |
2 | 0 | 3 | 1* | 19 |
3 | 495300698503 | 0 | 0 | 10 |
4 | 12 | 12 | 11 | 0 |
The smallest number is subtracted from all the cells
Stage | A | B | C | D |
1 | 50165444500 | 24130444508 | 36195444506 | 48260444502 |
2 | 0 | 2 | 0 | 19 |
3 | 1 | 0 | 0 | 11 |
4 | 12 | 11 | 10 | 0 |
From the table above all the zeros are covered by four lines. Therefore select row with one zero and cross its column.
Stage | A | B | C | D |
1 | 0* | 8 | 6 | 2 |
2 | 0 | 2 | 0* | 19 |
3 | 1 | 0* | 0 | 11 |
4 | 12 | 11 | 10 | 0* |
Choosing the cell from the original table
Stage | A | B | C | D |
1 | 39* | 27 | 30 | 37 |
2 | 46 | 40 | 43* | 27 |
3 | 37 | 34* | 35 | 27 |
4 | 30 | 27 | 29 | 42* |
The optimal assignment cost is 39+34+43+42=158
References
Winston, W. L., & Goldberg, J. B. (2004). Operations research: applications and algorithms (Vol. 3). Belmont^ eCalif Calif: Thomson/Brooks/Cole.
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